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## How many moles are there in silver nitrate?

From the table above, we can see that **1 Mole** of Silver Nitrate weighs about 169.87 grams. You can then say that the Formula Weight of Silver Nitrate is 169.87 grams. Note: The terms: Formula Weight and Molecular Weight are the same thing.

## How many moles are in 2.58 g of silver nitrate?

1 Expert Answer

1) (2.58 g AgNO_{3}) * (1 mole AgNO_{3} / 169.9 g AgNO_{3}) = **0.0152 mole AgNO**_{3}.

## How many moles are in AgNO3?

you find moles of AgNO3. That is 0.0132 g AgNO3 x 1 mol AgNO3/169.9 g = **7.77×10-5 moles**. Since there is 1 mole Ag and 1 mole NO3 per mole of AgNO3, this is also the number of moles of Ag+ and NO3- ions.

## How many molecules are there in 65 g of silver nitrate?

There are thus **65.9⋅g169.87⋅g⋅mol−1** × NA individual formula units of AgNO3 , where NA=Avogadro’s number, 6.022140857×1023⋅mol−1 .

## What is the mass of 1.23 moles of silver nitrate?

What mass of silver chromate is produced from 1.23 mol of silver nitrate. We can calculate the mass of silver nitrate using ration: m(AgNO_{3}) = n*M(AgNO_{3}) where n is number of moles; M is molar mass in g/mol. Answer: m (Ag_{2}CrO_{4}) = **204.18 g**.

## How many grams are in 7.40 moles of agno3?

Answer: The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles AgNO3, or **169.8731 grams**.