# Question: How many moles of oxygen are in Al2 SO4 3?

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## How many O are there in Al2 SO4 3?

Now for the grand tally: 2 aluminum atoms + 3 sulfur atoms + 12 oxygen atoms = 17 atoms total in each molecule.

## How many moles of oxygen are in aluminum sulfate?

Thus, 3.00 mole of Al2(SO4)3 A l 2 ( S O 4 ) 3 contains 18 mol of oxygen atoms.

## How many moles of oxygen is?

One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.

## How many atoms are in Al2 so42?

The brackets indicate that 3 must be multiplied by the number of atoms of each element: 3×1 sulfur, 3×4 oxygen. Now the number of votes: 2 aluminum atoms + 3 sulfur atoms + 12 oxygen atoms = 17 atoms in total in each molecule.

## What is the charge of SO4 3?

Al has a 3+ charge, and SO4 has a 2 charge.

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## How many atoms of aluminum sulfur and oxygen are in 3 molecules of aluminum sulfate?

the formula for aluminum sulfate is Al2(SO4)3. Then, in a formula unit of Al2(SO4)3 there are two aluminum ions and three sulfate ions; or two aluminum, three sulfur, and twelve oxygen atoms.

## How many moles of Aluminium sulphate will contain 0.25 mole of oxygen atom?

Answer: 1mole of al2(so4)3 contains 12 mole oxyzen atom. then 1 mole of oxygen atom is in 1/12mole of aluminium solphate. then 0.25 mole of oxygen atom is in 0.25/12 mole of aluminum solphate.

## How many moles of ions are there per mole of Al2 SO4 3?

For every mole of the ionic compound, there are 2 moles of aluminum and 3 moles of sulfate ions.

## What is 5 moles O2?

Therefore, 160 g of oxygen is present in 5 moles.

## How many O2 atoms are there in 3 moles of O2?

1 mole of O₂ contains 6.022 × 10²³ atoms. Thus, 3 moles O₂ would contain 3 × 6.022 × 10²³ atoms. Therefore, 3 moles of O₂ contain 18.066 × 10²³ atoms.

## How many oxygen molecules are in 5 moles?

Hence, number of moles of Oxygen in 5 Moles of CO = 5. The number of oxygen atoms present can be obtained by multiplying the moles of oxygen by Avogadro’s Number. So, number of oxygen atoms present = 5 x ( 6.023 x 10^23 ) = 30.115 x 10^23 nos.