# Question: How many moles of Cl2 are in 12 0 grams of Cl2?

Contents

## How many moles are in Cl2?

The approach is outlined below: 39.2 g Cl2(1 mole of Cl270.9 g Cl2)(6.022⋅1023molecules Cl21 mole Cl2)=3.33⋅1023 molecules Cl2 . Hence, the answer is 3.33⋅1023 molecules of Cl2. Note that 6.022⋅1023 is also known as Avogadro’s number, and it can be referred to as the number of molecules in one mole of that substance.

## What are the number of moles of chlorine in 14.2 grams of Cl2?

Similarly, the mass of the chlorine molecule is given as [14.2g] and it is known that the molecular mass of the chlorine molecule is [70.9g/mol]. Thus, the mole present in the chlorine molecule can be calculated by using the mole formula. Thus, [0.2mol] is present in [14.2g]of chlorine.

## How many moles are there in 123.2 g of Cl2?

So, we will get 1.159 mol of AlCl 3 if we react 123.2 g of Cl 2.

## How many moles are in 45g of Cl2?

= >0.6⋅mol Cl2 gas.

## How many CL are in a gram?

Centiliters to grams table

Centiliters Grams
1 cl 10 g
2 cl 20 g
3 cl 30 g
4 cl 40 g

## How do you find the moles of CL?

The mass of one mole of chlorine gas is its molar mass, and can be determined by multiplying its subscript by the molar mass of chlorine (atomic weight on the periodic table in g/mol), which is 35.45 g/mol .

THIS IS AMAZING:  Question: What is a dermatologist salary in South Africa?

## How many moles are in chlorine?

One mole of chlorine weighs 70 grams. Just like a dozen equals twelve, a mole equals Avogadro’s number of atoms or 6.02 × 1023. 6.02 × 1023 molecules of hydrogen would weigh 2 grams. An equal number of chlorine molecules would weigh 70 grams.

## How many moles are in 79.3 g of Cl2?

The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits…….

## How many moles are there in 123.2 g of cl₂?

We can add that conversion factor as another step in a calculation to make a mole-mass calculation, where we start with a given number of moles of a substance and calculate the mass of another substance involved in the chemical equation, or vice versa. So, we will get 1.159 mol of AlCl 3 if we react 123.2 g of Cl 2.