**Contents**show

## How many moles are there in silver nitrate?

From the table above, we can see that **1 Mole** of Silver Nitrate weighs about 169.87 grams. You can then say that the Formula Weight of Silver Nitrate is 169.87 grams. Note: The terms: Formula Weight and Molecular Weight are the same thing.

## How many moles of AgNO3 are in 169.9 g of AgNO3?

But in solution, you find moles of AgNO3. That is 0.0132 g AgNO3 x 1 mol AgNO3/169.9 g = **7.77×10-5 moles**.

## How much is a mole of silver?

The molar mass of silver is **107.9 g/mol**. Therefore: n moles of silver atoms will have a mass of (n TIMES 107.9) g.

## What is the N factor of AgNO3?

Equivalent weight = molar wt. / n- factor !!! and n factor for AgNO3 is **1 !!!**

## How many atoms are there in AgNO3?

In one silver nitrate formula unit, there are **3 oxygen ATOMS, 1 nitrogen ATOM, and 1 silver atom**.

## How do you calculate the normality of AgNO3?

So a 0.1N solution is: 16.987 grams diluted to a volume of 1 Liter.

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How to Make your own Silver Nitrate Standard Solutions.

Volumetric Flasks | Meniscus |
---|---|

Volumetric Flasks look like this. There are many sizes and styles. 1000 ml equals 1 Liter | Add Water until you have reached the mark on the flask like the example above. |

## How many moles is 79.3 g Cl2?

The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or **1.12 moles**, to the justified number of significant digits…….

## How do you find moles of Cl in AgCl?

**Key Concepts**

- (i) moles of AgCl
_{(}_{s}_{)}precipitated. moles = mass ÷ molar mass. - (ii) moles of chloride ion, Cl
^{–}, present. mole ratio AgCl:Cl^{–}is 1:1. - (iii) mass of chloride ion, Cl
^{–}, present in the seawater. mass = moles × molar mass.