# How much NaOH in moles is needed to neutralize the excess nitric acid?

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## How much NaOH is needed to neutralize the excess nitric acid?

Each mole of NaOH neutralizes 1 mole of acid. The 0.2 M slution of HNO3 contains 0.02 moles in 100 ml. The 4 M NaOH solution contains 4 millimoles per milliter. Therefore 5 ml of NaOH solution are required to neutralize the acid.

## How many moles of NaOH are needed to neutralize HCl?

A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.

## How do you calculate the number of moles needed to neutralize?

So, the solution will be neutralized when the number of moles of H+ equals the number of moles of OH.

1. Step 1: Calculate the number of moles of OH.
2. Molarity = moles/volume.
3. moles = Molarity x Volume.
4. moles OH = 0.02 M/100 milliliters.
5. moles OH = 0.02 M/0.1 liters.
6. moles OH = 0.002 moles.

## How much 1.00 m NaOH is needed to neutralize the H2SO4 solution?

From this you can see that it takes 2 moles NaOH per 1mole H2SO4.

## How do you neutralize HNO3?

For this example, nitric acid (HNO3) is neutralized with sodium hydroxide (NaOH), producing nitrate compounds in the form of sodium nitrate (NaNO3).

## What solution neutralizes nitric acid?

Nitric Acid HNO3:

The pH neutralization of Nitric acid is conventional and any inorganic base such as sodium hydroxide or lime can be used.

## How does sodium hydroxide reacts with nitric acid?

– According to the given equation, sodium hydroxide reacts with nitric acid to form sodium nitrate salt and water. This is an example of a neutralization reaction. – Sodium hydroxide is a strong base and nitric acid is a strong acid. – Strong acid reacts with a strong base to form salt and water.

## How many moles of NaOH were used in the titration?

Since 30 ml (or 0.03 liters) of NaOH was used for the titration, 0.03 liters · 0.1 moles/liter = 0.003 moles of NaOH was used to titrate the HCl. Since the mole ratio is 1:1, the same number of moles (0.003) of HCl must have been titrated.

## How do you calculate moles of HCl neutralized by antacids?

Therefore, the number of moles of HCl that reacted with the antacid should be equal to the total number of moles of HCl minus the number of moles of excess HCl. Take this amount and divide by the mass of the sample and you have your acid neutralizing capacity.

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## How do you neutralize NaOH?

Both acetic and citric acid can be used to neutralize NaOH. However, If you used dilute hydrochloric or sulphuric acid (phosphoric acid), and neutralize with those, the neutral pH could be available.

## How do you find the moles of NaOH added?

Step 1: Calculate the amount of sodium hydroxide in moles

1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
2. Amount of sodium hydroxide = 0.100 × 0.0250.
3. = 0.00250 mol.
4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
5. So the mole ratio NaOH:HCl is 1:1.

## How many moles are in NaOH?

Determining the Molar Mass of a Compound

The molar mass of the compound NaOH is 40 g/mol.