# How many moles of oxygen are present in one mole of KClO3?

Contents

## How many moles of O2 are in KClO3?

From looking at our balanced equation, we know that 2 moles of potassium chlorate produces 3 moles of oxygen, or O2 . So, our mole ratio of potassium chlorate to oxygen is 2:3 .

## How many moles are in KClO3?

​According to the equation 2 moles of KClO3 gives 3 moles of oxygen (O2). To obtain 6 moles of oxygen we multiply chemical equation by 2. Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

## How many moles of KClO3 must completely react?

You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen.

## What is the mole of O2?

One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.

## What are mole ratios?

Mole Ratio: is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation. The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.

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## How many moles of oxygen is produced from the decomposition of 6 moles of KClO3?

Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.

## How many moles of oxygen are produced when 3.0 moles of KClO3 decomposes completely?

(3/2)*(3.0) moles O2, or 4.5 moles of O2.

## How many moles of oxygen are produced when 2 mol of potassium chlorate KClO3 decompose quizlet?

Write all of the mole ratios present and show that the balanced equation obeys the law of conservation of mass. Two moles of potassium chloride (KCl) and three moles of oxygen (O2) are produced from the decomposition of two moles of potassium chlorate (KClO3). You just studied 11 terms!

## How many moles of oxygen can be obtained by the decomposition?

The correct answer of this question is 5 moles of oxygen gas can be produced during the electrolytic decomposition of 180 g of water.