# How many moles of AgCl would precipitate?

Contents

## How many moles of AgCl will precipitate?

2 moles because 2 Cl- ions are present as counter ion in the complex.

## How many moles of AgCl is produced?

In order to get the mass of AgCl, you have to multiply the produced moles of AgCl, which is 0.012 moles, with the molar mass of AgCl, which is 143.32 g/mol.

## How many moles of AgCl will be precipitated when an excess of AgNO3 is added to a molar solution of crCl H2O 5 Cl2?

[crCl(H2O)5]Cl2? Assuming that 1 litre of solution is taken.. It would give 2 moles of Cl . Hence, adding excess of AgNO3 will ppt out 2 moles of AgCl..

## How many moles of AgCl will be precipitated when excess of AgNO3 is added to one mole of CoCl3 4NH3?

When excess Ag+ ion is added to solutions of the CoCl3 6 NH3 and CoCl3 5 NH3 H2O complexes, three moles of AgCl are formed for each mole of complex in solution, as might be expected.

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## Which gives only 25% mole of AgCl when reacts with AgNO3?

3 NH 3 or [ Pt ( NH 3 ) 3 Cl 3 ] Cl gives only 25 % of AgCl as we can see than here 4 Cl are present , but only 1 mol of AgCl is obtained i . e . 1 4 × 100 = 25 % . This is because here the 3 Cl atoms are inside the coordination sphere while 1 Cl is outside , therefore 1 Cl is only available for AgNO 3 .

## How many grams of AgCl are produced by the reaction?

Therefore, the mass of AgCl formed by the reaction is 0.84 g.

## How do you find the moles of AgCl?

Divide the given mass m by the molecular weight W of AgCl, which is given as 143 g/mole. That gives the number of moles of AgCl. Since there is one atom of Ag in each molecule of AgCl, the number of moles of Ag equals the number of moles of AgCl.

## When an excess of AgNO₃ is added to the complex two moles of AgCl are precipitated the formula of the complex is?

When an excess of AgNO3 is added to the complex one mole of AgCl is precipitated. The formula of the complex is [CoCl2(NH3)4]Cl.

## How many moles of AgCl will be obtained when AgNO3 solution is completely?

of moles of AgCl obtained when excess AgNO_(3) is added to one mole of [Cr(NH_(3))_(4)Cl_(2)]Cl. [Cr(NH3)4Cl2]Cl ionises gives one Cl- ion. So it gives 1 mole AgCl ppt.

## What fraction of chlorine will be precipitated as AgCl?

– So, only these 2 chloride ions can be precipitated out by AgNO3 as AgCl. – So, the fraction of chloride precipitated is 2/3.

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