How many moles are there in 10 grams of sodium hydroxide?

How many moles is 10g of NaOH?

Answer: The answer is 39.99711. We assume you are converting between grams NaOH and mole.

How many moles are in 10g?

10/18 moles = 10/18 * 6 * 10^23 number of molecules = 3.33 * 10^23 molecules of water. Each molecule of water has 3 atoms, so the total number of atoms in 10g of water is 3*3.33*10^23 = 10^24.

How many moles are in NaOH?

The molar mass of the compound NaOH is 40 g/mol.

How do you find the moles of NaOH added?

Step 1: Calculate the amount of sodium hydroxide in moles

  1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
  2. Amount of sodium hydroxide = 0.100 × 0.0250.
  3. = 0.00250 mol.
  4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
  5. So the mole ratio NaOH:HCl is 1:1.

How many moles are in 11.5 g of NaOH?

The molar mass of Na is equal to 23g/mol. The formula to find out the number of moles is given by . Therefore the number of moles in 11.5g of sodium or Na is equal to which gives us 0.5.

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How many moles are present in 10 grams of H2O?

One mole of any substance weighs about the same as the molecular mass of that substance. Hence, there are [3.34times {10^{23}}] molecules of [{H_2}O] present in a 10 gram sample of [{H_2}O] .

How many moles of H2O are present in 10 grams of water?

=>Molar mass of H2O = 18 g mol​-1. 18 g of H2O contains = 6.022×1023 molecules. 10 g of H2O cotains =6.022×102318×10 = 3.34×1023 molecules.

How many moles are in 8 grams of NaOH?

The answer is 39.99711.

How many grams of NaOH are in 3 moles of NaOH?

A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL) , so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.

How many particles are in 7.5 moles?

Explanation: And Avogadro’s number , 6.022×1023⋅mol−1 specifies a molar quantity…… And so 7.5⋅mol×6.022×1023⋅mol−1≅4.5×1024 sulfur atoms .