# How many moles are present in 4 g of NaOH?

Contents

## How many moles are present in NaOH?

Converting Mass to Number of Moles

This the same as multiplying by the reciprocal of 40 g/mol. If the equation is arranged correctly, the mass units (g) cancel out and leave moles as the unit. There are 2.25 moles of NaOH in 90g of NaOH.

## How many moles of NaOH is in a sample of 400g?

Molecular mass of NaOH is 40g. 40g of NaOH contains 1 mole of NaOH. Then 400g of NaOH will contain 10 moles of NaOH.

240=0.05.

## How many moles are there in 5 gram of sodium hydroxide?

Moles = mass / molar mass

So, 0.125 moles are present in 5g of NaOH.

## How many grams of NaOH are in 3 moles of NaOH?

A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL) , so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.

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## How many moles are in 11.5 g of NaOH?

The molar mass of Na is equal to 23g/mol. The formula to find out the number of moles is given by . Therefore the number of moles in 11.5g of sodium or Na is equal to which gives us 0.5.

## How many grams are in 4.50 moles of sodium fluoride?

The mass of 4.5 moles of sodium fluoride is 189g.

## How many moles are there in 60g of sodium hydroxide NaOH?

Answer : The number of moles in 60 g of NaOH is 1.5 moles.

## How many moles are in 40g of sodium hydroxide?

Now take 120 grams NaOh and multiply this by 1 mol NaOH/ 40 grams NaOH. You can cancel out the grams and you have moles left. Now you do 120 x 1 / 40 and you get 3 moles of NaOH!

## How many moles are in 4.75 g of sodium hydroxide?

4.75 g of NaOH (1.19 x 101 mol NaOH) Answer: The molar mass of NaOH was solve in section A to be 40 g/mol.

## How do you find the moles of NaOH added?

Step 1: Calculate the amount of sodium hydroxide in moles

1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
2. Amount of sodium hydroxide = 0.100 × 0.0250.
3. = 0.00250 mol.
4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
5. So the mole ratio NaOH:HCl is 1:1.

## How many moles of NaOH are there in 225.0 ml of 2.50 M NaOH?

Hence, n = 2.50 / 0.225L = 11.111 moles.