# How many Faraday of electricity is required to reduce 1 mole of kmno4 minus ions to Mn 2 ions?

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## How many Faraday of electricity is required to reduce 1 mole of mno4 minus ions to Mn 2 ions?

How many faradays are required to reduce one moleof MnO_(4)^(-) to Mn^(2+)? Number of faradays is equal to the change in oxidation state. Since oxidation state of Mn decreases by 5 units (from +7 to +2), five faradays is needed.

## How many faradays are involved in conversion of a mole of to a 1 B 2 C 3 D 4 E 5?

Answer: 1 Faraday per 1 mole because the difference between oxidation no. of both Fes is 4-3=1.

93×105C.

5. 62×105C.

## How many Faradays are required to reduce 1 mole of Bro 3 2b are?

1 mol contains 6.023*10^{23} atoms. 3*6.023*10^{23}*1.602*10^{ -19}=3*96500;Coulombs . We know 96500 ;Coulombs which is equal to 1 Faraday . The number of Faradays required is frac{3*96500}{96500} =3;Faradays .

2×96500 C.

## How many Faradays are needed to convert moles?

i.e., when 1 mole of MnO-4 changes to Mn2+ 5 faradays of charge is required. i.e., 6 faradays of charge is required.

## What is the charge of 1 mole of electrons?

Charge on a single electron is 1.6 x 10^-16 Coulomb. There are 6.02 x 10^23 electrons per mole. So we get the charge on one mole of electrons as (1.6 x 10^-16) x (6.02 x 10^23) = 96500 C which is also called 1 Faraday.

## How much charge is required for the reduction of 1 mole?

where Q denotes the charge, n is the number of moles and F is the value of Faraday. Hence, we can say that the correct option is (D), that is the charge required for reducing 1 mole of MnO−4 to Mn2+ is 4.825×105C.

9650C.

1F. 3F.