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## How many moles are in 20 grams of NaOH?

Answer: Number of moles which make up 20 grams of NaOH = (20 grams × 1 Mole)/(40 grams) = **0.5 moles**.

## How many moles are in NaOH?

Determining the Molar Mass of a Compound

The molar mass of the compound NaOH is **40 g/mol**.

## How many moles are in 80g of NaOH?

= 80 / 40= **2 mol** .

## How do you calculate 1 mole of NaOH?

molarity = no. of moles of solute / 1 liter . * one moles of sodium hydroxide = **40 gm of sodium hydroxide**. so we can said ; if want prepare 1 molar NaOH solution then we need 40 gm NaOH dissolve in one liter of water so it became one 1 molar NaOH solution.

## How many moles are in 30g of NaOH?

The molar mass of NaOH is 40.0 g/mol, so there are **0.75mol**⋅40.0g/mol=30g of NaOH, 30.

## How many moles are in 11.5 g of NaOH?

The molar mass of Na is equal to 23g/mol. The formula to find out the number of moles is given by . Therefore the number of moles in 11.5g of sodium or Na is equal to which gives us **0.5**.

## How do I calculate moles?

So in order to calculate the number of moles of any substance present in the sample, we simply **divide the given weight of the substance by its molar mass**. Where ‘n’ is the number of moles, ‘m’ is the given mass and ‘M’ is the molar mass.

## How many moles of NaOH are present in 27 ml of 0.015 M NaOH?

=**0.045** (ans).

## How many grams of NaOH are in 3 moles of NaOH?

A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL) , so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=**30g** of NaOH, 30.

## How many moles of sodium hydroxide are in 8g of sodium hydroxide?

The answer is **39.99711**.

## How many moles of NaOH are present in 160g of NaOH?

Question = Calculate the moles of Sodium hydroxide contained in 160 g of it. Answer = 160 g of Sodium hydroxide. 160 g of Sodium hydroxide = 1 mol × 160 / 40 = **4 mol**.

## How many particles are in 7.5 moles?

Explanation: And Avogadro’s number , 6.022×1023⋅mol−1 specifies a molar quantity…… And so 7.5⋅mol×6.022×1023⋅mol−1≅**4.5×1024 sulfur atoms** .