**Contents**show

## How many moles are present in NaCl?

**One mol** of NaCl (6.02 x1023 formulas) has a mass of 58.44 g.

## How many moles are in 1000mL?

Therefore, if we divide 1000mL by 1000mL we will obtain a value of **1L**. Boom, there would be 0.5 moles of NaCl!

## How many mL is 5grams?

Grams to mL conversions (water)

Grams to mL | Grams to mL |
---|---|

3 grams = 3 mL | 150 grams = 150 mL |

4 grams = 4 mL | 200 grams = 200 mL |

5 grams = 5 mL |
250 grams = 250 mL |

6 grams = 6 mL | 300 grams = 300 mL |

## How may grams of NaCl do you need to make 500 ml of a 1 M NaCl solution?

1 Expert Answer

Now we know we want 1 mol per liter, and 500 mL is half a liter, so we want half a mol – or **29.22 grams**.

## How do you make 100ml of 1M NaCl?

= c_{2}/c_{1}) is 0.1M/1M = **1/10**. To make 100 ml of 0.1M NaCl, one would pipette 10 ml of stock 1M NaCl into a 100 ml volumetric flask, and bring the total volume to 100 ml with water.

## How many moles of sodium and chloride are in NaCl?

Sodium chloride, commonly known as salt, is an ionic compound with the chemical formula NaCl, representing a 1:1 ratio of sodium and chloride ions. So, we can say that the number of moles associated with 1.17g sodium chloride is **0.02moles**.

## How do I calculate moles?

**How to find moles?**

- Measure the weight of your substance.
- Use a periodic table to find its atomic or molecular mass.
- Divide the weight by the atomic or molecular mass.
- Check your results with Omni Calculator.

## How do you find moles from ML and molarity?

To calculate the number of moles in a solution given the molarity, we **multiply the molarity by total volume of the solution in liters**.

## What is the mole formula?

Avogadro’s number is a very important relationship to remember: **1 mole = 6.022×1023 6.022 × 10 23 atoms**, molecules, protons, etc. To convert from moles to atoms, multiply the molar amount by Avogadro’s number. To convert from atoms to moles, divide the atom amount by Avogadro’s number (or multiply by its reciprocal).